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>>> t=time.time();data=r.get("http://localhost:8080//peekLatestMessage?count=10").text;print(time.time()-t) 2.0292623043060303
获取消息一次要两秒,发消息也差不多,稍微再多点
建议使用websocket上报消息
@rainchan 好的,我试试,谢谢你